Fibonacci Sequence
// Function to calculate the nth Fibonacci numberint fibonacci(int n) { // Base case: If n is 0 or 1, return n // This is because the Fibonacci series starts with 0 and 1 if(n <= 1) return n;
// Recursive case: Fibonacci of n is sum of Fibonacci of (n-1) and (n-2) // The function calls itself to calculate the previous two Fibonacci numbers return fibonacci(n - 1) + fibonacci(n - 2);}Example Walkthrough:
fibonacci(5)callsfibonacci(4)andfibonacci(3):fibonacci(5)=fibonacci(4)+fibonacci(3)
fibonacci(4)callsfibonacci(3)andfibonacci(2):fibonacci(4)=fibonacci(3)+fibonacci(2)
fibonacci(3)callsfibonacci(2)andfibonacci(1):fibonacci(3)=fibonacci(2)+fibonacci(1)
fibonacci(2)callsfibonacci(1)andfibonacci(0):fibonacci(2)=fibonacci(1)+fibonacci(0)- Since
fibonacci(1)is1andfibonacci(0)is0, return1 + 0 = 1.
- Now, substitute the results step by step:
fibonacci(3) = 1 + 1 = 2fibonacci(4) = 2 + 1 = 3fibonacci(5) = 3 + 2 = 5
Final Result:
For n = 5, the Fibonacci number is 5.